{"id":17725,"date":"2024-05-04T00:34:35","date_gmt":"2024-05-04T00:34:35","guid":{"rendered":"https:\/\/soicau5079.minhngocxoso.com\/?p=17725"},"modified":"2024-05-04T00:34:35","modified_gmt":"2024-05-04T00:34:35","slug":"top-5-pp-choi-lo-hieu-qua-cuc-cao","status":"publish","type":"post","link":"https:\/\/xosotructiep88.com\/top-5-pp-choi-lo-hieu-qua-cuc-cao\/","title":{"rendered":"top 5 pp ch\u01a1i l\u00f4 hi\u1ec7u qu\u1ea3 c\u1ef1c cao"},"content":{"rendered":"
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Xin ch\u00e0o c\u00e1c b\u1ea1n, h\u00f4m nay s\u1ebd chia s\u1ebb cho c\u00e1c b\u1ea1n 5 ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i l\u00f4 m\u00e0 ch\u00fang t\u00f4i th\u1ea5y hi\u1ec7u qu\u1ea3 r\u1ea5t cao. H\u00e3y theo d\u00f5i b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y nh\u00e9:<\/p>\n\n\n\n
N\u1ebfu th\u1ea5y trong t\u1ea5t c\u1ea3 c\u00e1c ng\u00e0y xem k\u1ebft qu\u1ea3 gi\u1ea3i m\u00e0 c\u00f3 xu\u1ea5t hi\u1ec7n 3 con lotto li\u1ec1n nhau. VD: ng\u00e0y 2-3 c\u00f3 3 con lotto 30,31,32 v\u00e0 ng\u00e0y 3-3; 4-3; 5-3 3 con lotto 30-31-32 ch\u01b0a v\u1ec1 l\u1ea1i con n\u00e0o th\u00ec ta s\u1ebd b\u1eaft \u0111\u1ea7u l\u1ecdc s\u1ed1 v\u00e0 ch\u1ecdn ra 2 con nu\u00f4i trong 2 ng\u00e0y, c\u00f9ng l\u1eafm th\u00ec m\u1edbi ph\u1ea3i \u0111\u1ebfn ng\u00e0y th\u1ee9 3<\/p>\n\n\n\n
N\u1ebfu tr\u01b0\u1eddng h\u1ee3p trong 1 gi\u1ea3i xu\u1ea5t hi\u1ec7n 3 s\u1ed1 gi\u1ed1ng nhau ta l\u00e0m nh\u01b0 sau :+ Gi\u1ea3i 5 s\u1ed1 : lo\u1ea1i 3 con s\u1ed1 gi\u1ed1ng nhau l\u1ea5y con l\u1edbn nh\u1ea5t. VD : 11125 l\u1ea5y con 5+ Gi\u1ea3i 4 s\u1ed1 : l\u1ea5y con c\u00f2n l\u1ea1i. VD 1115 l\u1ea5y con 5+ Gi\u1ea3i 3 s\u1ed1 : 111 l\u1ea5y con 0 d\u00f9 l\u00e0 3 s\u1ed1 n\u00e0o c\u0169ng l\u1ea5y s\u1ed1 0Khi l\u1ea5y \u0111\u01b0\u1ee3c s\u1ed1 ta gh\u00e9p vs con b\u00e9 nh\u1ea5t c\u1ee7a Gi\u1ea3i \u0110B kh\u00e1c con 0. VD : 01234 ta l\u1ea5y con 1. C\u00f3 1 c\u1eb7p s\u1ed1 \u0111\u00e1nh trong 3 ng\u00e0y!<\/p>\n\n\n\n
+ Ta l\u1ea5y k\u1ebft qu\u1ea3 gi\u1ea3i \u0110B c\u1ee7a ng\u00e0y h\u00f4m nay vd : 12345 ta s\u1ebd c\u00f3 1+2+3+4+5=15 \u2013> 1+5=6 -> t\u1eeb \u0111\u00e2y ta c\u00f3 con 6 l\u1ea5y con 6 gh\u00e9p v\u1edbi 0 ta c\u00f3 c\u1eb7p 060 \u0111\u00e1nh trong 3 ng\u00e0y, l\u1ea5y con 6 gh\u00e9p v\u1edbi 8 ta c\u00f3 c\u1eb7p 686 \u0111\u00e1nh trong 3 ng\u00e0y. PP th\u1eddi \u0111i\u1ec3m hi\u1ec7n nay gh\u00e9p 0 \u0111ang \u0103n ngay ng\u00e0y h\u00f4m sau<\/p>\n\n\n\n + PP n\u00e0y c\u00e1c b\u1ea1n c\u1ea7n \u0111\u1ec3 \u00fd \u1edf gi\u1ea3i 4 s\u1ed1 n\u1ebfu nh\u01b0 c\u00f3 d\u1ea1ng 1231,1236\u2026.vv. 2 s\u1ed1 gi\u1eefa \u0111\u01b0\u1ee3c k\u1eb9p b\u1edfi 1 s\u1ed1 ho\u1eb7c k\u1eb9p v\u1edbi 1 b\u00f3ng c\u1ee7a n\u00f3 ta l\u1ea5y 2 con gi\u1eefa \u0111\u1ec3 quan s\u00e1t cho ng\u00e0y h\u00f4m sau, v\u1ec1 th\u00ec s\u1ebd b\u1ecf, ko v\u1ec1 nh\u1ea3y v\u00e0o ng\u00e0y th\u1ee9 2( r\u1ea5t hay v\u1ec1 v\u00e0o ng\u00e0y th\u1ee9 2) v\u00e0 th\u1ee9 3. VD Ng\u00e0y 24-2 : G5_5 3523 L\u1ea5y c\u1eb7p 525 quan s\u00e1t h\u00f4m 25-2 kh\u00f4ng v\u1ec1, 26-2 nh\u1ea3y v\u00e0o \u0111\u00e1nh c\u1ea3 c\u1eb7p \u0111\u1ed5 c\u1ea3 c\u1eb7p! nh\u01b0 th\u1ebf n\u00e0y c\u0169ng c\u00f3 th\u1ec3 g\u1ecdi l\u00e0 k\u1eb9t : 3528\u2026<\/p>\n\n\n\n + Quan s\u00e1t c\u00e1c s\u1ed1 t\u1eeb gi\u1ea3i 6 \u0111\u1ebfn gi\u1ea3i 7 v\u00e0 th\u1ee9 t\u1ef1 l\u1ea7n l\u01b0\u1ee3t t\u1eeb G6_1 \u2013> G6_2 \u2013> G6_3\u2013G7_1\u2026\u2013> G7_4.V\u00ed d\u1ee5 : G6_1 234 ; G6_2 345 ; G6_3 678 ; G7_1 28 V\u1eady th\u00ec G6_1 v\u00e0 gi\u1ea3i sau n\u00f3 2 gi\u1ea3i l\u00e0 G7_1 c\u00f3 chung 1 \u0111\u1ea7u l\u00e0 2 v\u1eady l\u00e0 tr\u00f9ng \u0111\u1ea7u ta l\u1ea5y 2 \u0111\u1ea7u c\u1ee7a 2 gi\u1ea3i \u1edf gi\u1eefa ch\u00fang l\u00e0 3 v\u00e0 6 gh\u00e9p v\u00e0o th\u00e0nh c\u1eb7p 636 \u0111\u00e1nh trong 3 ng\u00e0y..<\/p>\n\n\n\n + N\u1ebfu tr\u00f9ng \u0111\u00edt th\u00ec tu\u01a1ng t\u1ef1 G6_2 123 ; G6_3 456 G7_1 78 G7_2 23 Ta \u0111\u1ec3 \u00fd th\u1ea5y gi\u1ea3i G6_2 v\u00e0 gi\u1ea3i sau n\u00f3 2 gi\u1ea3i l\u00e0 G7_2 c\u00f3 chung \u0111\u00edt l\u00e0 3 ta l\u1ea5y 2 \u0111\u00edt \u1edf gi\u1eefa l\u00e0 6 v\u00e0 8 th\u00e0nh c\u1eb7p 686 \u0111\u00e1nh trong 3 ng\u00e0y. N\u1ebfu \u0103n ngay h\u00f4m sau ti\u1ebfp t\u1ee5c nu\u00f4i 3 ng\u00e0y v\u00ec tr\u00f9ng \u0111\u00edt m\u00e0 \u0103n ngay h\u00f4m \u0111\u1ea7u s\u1ebd th\u01b0\u1eddng \u0103n ti\u1ebfp v\u00e0o ng\u00e0y h\u00f4m sau.<\/p>\n\n\n\n V\u1edbi 5 ph\u01b0\u01a1ng ph\u00e1p tr\u00ean \u0111\u00e2y c\u00e1c b\u1ea1n h\u00e3y m\u1ea1nh d\u1ea1n \u00e1p d\u1ee5ng v\u00e0 tr\u1ea3i nghi\u1ec7m nh\u00e9, kh\u1ea3 n\u0103ng tr\u00fang \u0111\u01b0\u1ee3c song th\u1ee7 l\u00f4 c\u0169ng nh\u01b0 b\u1ea1ch th\u1ee7 l\u00f4 kh\u00e1 cao nh\u00e9. Ch\u00fac ae \u0111\u1ea1i th\u1eafng. <\/p>\n\n\n <\/p>\r\nPh\u01b0\u01a1ng ph\u00e1p 4: Nu\u00f4i lotto khung 2 ng\u00e0y<\/h2>\n\n\n\n
Ph\u01b0\u01a1ng ph\u00e1p 5: Tr\u00f9ng \u0111\u1ea7u \u2013 Tr\u00f9ng \u0110\u00edt<\/h2>\n\n\n\n